What is the inflection f(x)=x^3-4x^2-16x+9 ?

The inflection f(x)=x^3-4x^2-16x+9 is (4/3 ,-461/27)

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inflection f(x)=x^3-4x^2-16x+9

inflection points

f (x) = x^{3} - 4 x^{2} - 16 x + 9

(\frac{4}{3}, - \frac{461}{27})

Solution steps

f^{''} (x) = 6 x - 8

Find intervals:

Concave Downward

: - \infty < x < \frac{4}{3},

Concave Upward

: \frac{4}{3} < x < \infty

Plug

x = \frac{4}{3}

into

x^{3} - 4 x^{2} - 16 x + 9 : - \frac{461}{27}

(\frac{4}{3}, - \frac{461}{27})

y = lo g_{5} (x) - 9

(4, 11), (9, 26)

f (x) = (x + 2)^{\frac{1}{2}}

y = 8

f (x) = \frac{( x + 1 ) ^{2}}{x ^{2} - 3 x - 4}

What is the inflection f(x)=x^3-4x^2-16x+9 ?
The inflection f(x)=x^3-4x^2-16x+9 is (4/3 ,-461/27)