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Popular >

distance (-4,-3),(-1,-1)

Solution

distance

(- 4, - 3), (- 1, - 1)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 4, - 3)

and

(- 1, - 1)

is

= (- 1 - (- 4))^{2} + (- 1 - (- 3))^{2}

Simplify

= 13

Popular Examples

inverse of f(x)=\sqrt[5]{x}+1 inverse

domain of f(x)=-sqrt(x+3)-2 domain

f (x) = - x + 3 - 2

perpendicular y=-1/9 x-8/9 ,(1,-4)perpendicular

y = - \frac{1}{9} x - \frac{8}{9}, (1, - 4)

range of y=arccos(x)range

y = arccos (x)

periodicity of sin(2.8x+0.9)+0.3 periodicity

sin (2.8 x + 0.9) + 0.3

Frequently Asked Questions (FAQ)

What is the distance (-4,-3),(-1,-1) ?
The distance (-4,-3),(-1,-1) is square root of 13