What is the domain of sqrt(36-x^2)+sqrt(x+1) ?

The domain of sqrt(36-x^2)+sqrt(x+1) is -1<= x<= 6

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domain of sqrt(36-x^2)+sqrt(x+1)

domain

36 - x^{2} + x + 1

- 1 \leq x \leq 6

Interval Notation

[- 1, 6]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 6

The function domain

- 1 \leq x \leq 6

x^{2} - 10 x + 16

y = - \frac{1}{4} x + 5

9 x - 5

f (x) = \frac{x ^{2} - x - 2}{x - 2}

f (x) = 2 x^{2} - 6 x^{4}

What is the domain of sqrt(36-x^2)+sqrt(x+1) ?
The domain of sqrt(36-x^2)+sqrt(x+1) is -1<= x<= 6