What is the asymptotes of 5/(x^2-9) ?

The asymptotes of 5/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of 5/(x^2-9)

asymptotes

\frac{5}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{5}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{5}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{5}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

f (x) = x + y = 2

f (x) = \frac{( 1 )}{x + 2} + 3

f (x) = x^{3} - 6 x^{2} + 9 x + 1

5 tan (2 x + π)

\frac{2}{2 x - 1}

What is the asymptotes of 5/(x^2-9) ?
The asymptotes of 5/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0