What is the extreme f(x)=x^3-6x^2+9x+1 ?

The extreme f(x)=x^3-6x^2+9x+1 is Maximum(1,5),Minimum(3,1)

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extreme f(x)=x^3-6x^2+9x+1

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 1

Maximum (1, 5), Minimum (3, 1)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x + 1 : 5

Maximum (1, 5)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x + 1 : 1

Minimum (3, 1)

Maximum (1, 5), Minimum (3, 1)

5 tan (2 x + π)

\frac{2}{2 x - 1}

lo g_{2} (x + 2) - 4

y = \frac{x + 2}{x ^{2} - x - 2}

f (x) = x^{2} + 3 x + 1

What is the extreme f(x)=x^3-6x^2+9x+1 ?
The extreme f(x)=x^3-6x^2+9x+1 is Maximum(1,5),Minimum(3,1)