What is the critical (0.23x)/(x^2+25) ?

The critical (0.23x)/(x^2+25) is x=-5,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical (0.23x)/(x^2+25)

critical points

\frac{0.23 x}{x ^{2} + 25}

x = - 5, x = 5

Solution steps

\frac{0.23 x}{x ^{2} + 25}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 5

Identify critical points not in

f (x)

domain

Domain of

\frac{0.23 x}{x ^{2} + 25} : - \infty < x < \infty

All critical points are in domain

x = - 5, x = 5

f (x) = sin (\frac{2 π x}{3} - 3 π)

f (x) = \frac{1}{2} x - 4

f (x) = \frac{x ^{3} + 5 x ^{2}}{7 x ^{2} - 3}

f (x) = - 4 cos (x) + 4

\frac{- 3}{x - 2} - 1

What is the critical (0.23x)/(x^2+25) ?
The critical (0.23x)/(x^2+25) is x=-5,x=5