What is the domain of f(x)=(x^3+5x^2)/(7x^2-3) ?

The domain of f(x)=(x^3+5x^2)/(7x^2-3) is x sqrt(3/7)

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domain of f(x)=(x^3+5x^2)/(7x^2-3)

domain

f (x) = \frac{x ^{3} + 5 x ^{2}}{7 x ^{2} - 3}

x < - \frac{3}{7} or - \frac{3}{7} < x < \frac{3}{7} or x > \frac{3}{7}

Interval Notation

(- \infty, - \frac{3}{7}) \cup (- \frac{3}{7}, \frac{3}{7}) \cup (\frac{3}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{7}, x = - \frac{3}{7}

The function domain

x < - \frac{3}{7} or - \frac{3}{7} < x < \frac{3}{7} or x > \frac{3}{7}

f (x) = - 4 cos (x) + 4

\frac{- 3}{x - 2} - 1

f (x) = \frac{x + 3}{8 - x}

x^{4} - 4 x^{3} + 10

y = - x^{3} + 12 x - 16

What is the domain of f(x)=(x^3+5x^2)/(7x^2-3) ?
The domain of f(x)=(x^3+5x^2)/(7x^2-3) is x<-sqrt(3/7)\lor-sqrt(3/7)<x<sqrt(3/7)\lor x>sqrt(3/7)