What is the domain of f(x)=(sqrt(x-2))/(x-9) ?

The domain of f(x)=(sqrt(x-2))/(x-9) is 2 9

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domain of f(x)=(sqrt(x-2))/(x-9)

domain

f (x) = \frac{x - 2}{x - 9}

2 \leq x < 9 or x > 9

Interval Notation

[2, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

2 \leq x < 9 or x > 9

f (x) = - 9 x + 9

sin (π t)

y = \frac{3}{2} x - 3

f (x) = \frac{15 - 2 x}{3}

y + 4 = - \frac{4}{5} (x + 5)

What is the domain of f(x)=(sqrt(x-2))/(x-9) ?
The domain of f(x)=(sqrt(x-2))/(x-9) is 2<= x<9\lor x>9