What is the perpendicular y= 3/2 x-3 ?

The perpendicular y= 3/2 x-3 is y=-2/3 x+b

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perpendicular y= 3/2 x-3

perpendicular

y = \frac{3}{2} x - 3

y = - \frac{2}{3} x + b

Solution steps

Find the slope of

y = \frac{3}{2} x - 3 : m = \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{3}

Line with slope m=

- \frac{2}{3} : y = - \frac{2}{3} x + b

y = - \frac{2}{3} x + b

f (x) = \frac{15 - 2 x}{3}

y + 4 = - \frac{4}{5} (x + 5)

f (x) = \frac{1}{x ^{2} - 2 x - 3}

f (x) = (2 x - 3)^{2} - 1

f (x) = \frac{7}{x ^{2} + 1}

What is the perpendicular y= 3/2 x-3 ?
The perpendicular y= 3/2 x-3 is y=-2/3 x+b