What is the inverse of y=((3x-4))/(-2x+2) ?

The inverse of y=((3x-4))/(-2x+2) is -(-4-2x)/(3+2x)

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inverse of y=((3x-4))/(-2x+2)

inverse

y = \frac{( 3 x - 4 )}{- 2 x + 2}

- \frac{- 4 - 2 x}{3 + 2 x}

Solution steps

y = \frac{3 x - 4}{- 2 x + 2}

Replace

x

with

y

x = \frac{3 y - 4}{- 2 y + 2}

Solve for

y, x = \frac{3 y - 4}{- 2 y + 2}

- \frac{- 4 - 2 x}{3 + 2 x}

y = x^{2} - 2

f (x) = 9 x + 3

f (x) = ln (x - 2)

f (x) = g (x) = (x + 3) 2 - 1

What is the inverse of y=((3x-4))/(-2x+2) ?
The inverse of y=((3x-4))/(-2x+2) is -(-4-2x)/(3+2x)