Solution
vertices
Solution
Solution steps
The parabola parameters are:
Simplify
Plug in to find the value
Therefore the parabola vertex is
If then the vertex is a maximum value
If then the vertex is a minimum value
Popular Examples
domain of f(x)=sqrt(x^2)-9domain inverse of f(x)=e^x-4inverse intercepts of (200)/(0.9+0.1e^{2x)}intercepts critical x/(x^2-6x+8)critical points inverse of f(x)=7sqrt(x+7)-10inverse
Frequently Asked Questions (FAQ)
What is the vertices y=x^2-10x+16 ?
The vertices y=x^2-10x+16 is Minimum (5,-9)