What is the asymptotes of f(x)=ln((x+1)/(x-1)) ?

The asymptotes of f(x)=ln((x+1)/(x-1)) is Vertical: x=-1,x=1,Horizontal: y=0

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asymptotes of f(x)=ln((x+1)/(x-1))

asymptotes

f (x) = ln (\frac{x + 1}{x - 1})

Vertical : x = - 1, x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

ln (\frac{x + 1}{x - 1}) : x = - 1, x = 1

Horizontal Asymptotes of

ln (\frac{x + 1}{x - 1}) : y = 0

Slant Asymptotes of

ln (\frac{x + 1}{x - 1}) :

None

Vertical : x = - 1, x = 1, Horizontal : y = 0

\frac{x ^{2} + 7 x + 12}{- 2 x ^{2} - 2 x + 12}

f (x) = \frac{( 2 x - 3 )}{( x - 2 ) ( x + 3 )}

f (x) = x^{2} - 3 x

- (x + 3)^{2}

f (x) = x^{2} - 4 x - 5

What is the asymptotes of f(x)=ln((x+1)/(x-1)) ?
The asymptotes of f(x)=ln((x+1)/(x-1)) is Vertical: x=-1,x=1,Horizontal: y=0