What is the domain of f(x)=sqrt((x-1)/(ln(x^2))) ?

The domain of f(x)=sqrt((x-1)/(ln(x^2))) is -1 1

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domain of f(x)=sqrt((x-1)/(ln(x^2)))

domain

f (x) = \frac{x - 1}{ln ( x ^{2} )}

- 1 < x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- 1, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

- 1 < x < 0 or 0 < x < 1 or x > 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 0 or 0 < x < 1 or x > 1

f (x) = lo g_{a} (x)

2 x^{3} - 24 x - 6

f (x) = \frac{x}{2} + 1

f (x) = 1 - 2^{- x}

f (x) = \frac{4 x - 3}{6 - 2 x}

What is the domain of f(x)=sqrt((x-1)/(ln(x^2))) ?
The domain of f(x)=sqrt((x-1)/(ln(x^2))) is -1<x<0\lor 0<x<1\lor x>1