What is the inverse of f(x)=(4x-3)/(6-2x) ?

The inverse of f(x)=(4x-3)/(6-2x) is -(-3-6x)/(2(2+x))

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inverse of f(x)=(4x-3)/(6-2x)

inverse

f (x) = \frac{4 x - 3}{6 - 2 x}

- \frac{- 3 - 6 x}{2 ( 2 + x )}

Solution steps

y = \frac{4 x - 3}{6 - 2 x}

Replace

x

with

y

x = \frac{4 y - 3}{6 - 2 y}

Solve for

y, x = \frac{4 y - 3}{6 - 2 y}

- \frac{- 3 - 6 x}{2 ( 2 + x )}

f (x) = lo g_{10} (2 - x)

f (x) = x^{4} - 3 x^{3} + 3 x^{2} + 1

(0, 8), (24.08, 0)

- 2 + 3 sin (2 x + \frac{π}{4})

f (x) = (- 5 x + 1)^{2}

What is the inverse of f(x)=(4x-3)/(6-2x) ?
The inverse of f(x)=(4x-3)/(6-2x) is -(-3-6x)/(2(2+x))