What is the inverse of-16(x+7)^2-3 ?

The inverse of-16(x+7)^2-3 is sqrt(-(x+3)/(16))-7,-sqrt(-(x+3)/(16))-7

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inverse of-16(x+7)^2-3

inverse

- 16 (x + 7)^{2} - 3

- \frac{x + 3}{16} - 7, - - \frac{x + 3}{16} - 7

Solution steps

y = - 16 (x + 7)^{2} - 3

Replace

x

with

y

x = - 16 (y + 7)^{2} - 3

Solve for

y, x = - 16 (y + 7)^{2} - 3

- \frac{x + 3}{16} - 7, - - \frac{x + 3}{16} - 7

\frac{x ^{2} - 4 x + 6}{x + 4}

- \frac{1}{4} (x + 3)^{2} - 5

f (x) = \frac{ln ( 1 + ∣ x + 3 ∣ )}{ln ( x )}

(- 4, 2), (6, 4)

y = \frac{8}{x ^{2} - 6 x + 8}

What is the inverse of-16(x+7)^2-3 ?
The inverse of-16(x+7)^2-3 is sqrt(-(x+3)/(16))-7,-sqrt(-(x+3)/(16))-7