What is the inverse of f(x)=7x^2-3 ?

The inverse of f(x)=7x^2-3 is sqrt((x+3)/7),-sqrt((x+3)/7)

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inverse of f(x)=7x^2-3

inverse

f (x) = 7 x^{2} - 3

\frac{x + 3}{7}, - \frac{x + 3}{7}

Solution steps

y = 7 x^{2} - 3

Replace

x

with

y

x = 7 y^{2} - 3

Solve for

y, x = 7 y^{2} - 3

\frac{x + 3}{7}, - \frac{x + 3}{7}

f (x) = 2 n - 2

f (x) = 3 x - 6 x^{3}

f (x) = 8 x + 13 x^{\frac{8}{13}}

f (x) = x^{5} - 3 x

f (x) = \frac{x}{4 x}

What is the inverse of f(x)=7x^2-3 ?
The inverse of f(x)=7x^2-3 is sqrt((x+3)/7),-sqrt((x+3)/7)