What is the inverse of f(x)=1+\sqrt[3]{x} ?

The inverse of f(x)=1+\sqrt[3]{x} is x^3-3x^2+3x-1

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inverse of f(x)=1+\sqrt[3]{x}

inverse

x^{3} - 3 x^{2} + 3 x - 1

Solution steps

Replace

x

with

y

Solve for

x^{3} - 3 x^{2} + 3 x - 1

f (x) = x x + 6

x^{4} + 2 x^{3} - 3 x^{2} - 4 x + 4

f (x) = 6 x - 38

f (x) = 2^{x - 1}

What is the inverse of f(x)=1+\sqrt[3]{x} ?
The inverse of f(x)=1+\sqrt[3]{x} is x^3-3x^2+3x-1