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Popular >

inflection f(x)=x^3-3x^2-9x+2

Solution

inflection points

f (x) = x^{3} - 3 x^{2} - 9 x + 2

Solution

(1, - 9)

Solution steps

f^{''} (x) = 6 x - 6

Find intervals:

Concave Downward

: - \infty < x < 1,

Concave Upward

: 1 < x < \infty

Plug

x = 1

into

x^{3} - 3 x^{2} - 9 x + 2 : - 9

(1, - 9)

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y = 1 - \frac{x}{8}

inverse of f(x)=\sqrt[4]{x}+6 inverse

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\frac{7 + x}{3 - x}

inverse of 2/3 (x-2)^3+6 inverse

\frac{2}{3} (x - 2)^{3} + 6

domain of sec^2(x)domain

sec^{2} (x)

Frequently Asked Questions (FAQ)

What is the inflection f(x)=x^3-3x^2-9x+2 ?
The inflection f(x)=x^3-3x^2-9x+2 is (1,-9)