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Popular >

distance (-4,-5),(2,1)

Solution

distance

(- 4, - 5), (2, 1)

Solution

62

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 4, - 5)

and

(2, 1)

is

= (2 - (- 4))^{2} + (1 - (- 5))^{2}

Simplify

= 62

Popular Examples

domain of f(x)=(x+1)/x domain

f (x) = \frac{x + 1}{x}

domain of f(x)=-x-1 domain

f (x) = - x - 1

inverse of f(x)=(x+10)^7 inverse

f (x) = (x + 10)^{7}

parity f(x)=3x^3+2x^2+1 parity

f (x) = 3 x^{3} + 2 x^{2} + 1

extreme f(x)=e^{x^2-4}extreme points

f (x) = e^{x^{2} - 4}

Frequently Asked Questions (FAQ)

What is the distance (-4,-5),(2,1) ?
The distance (-4,-5),(2,1) is 6sqrt(2)