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Popular >

extreme f(x)=e^{x^2-4}

Solution

extreme points

f (x) = e^{x^{2} - 4}

Solution

Minimum (0, \frac{1}{e ^{4}})

Solution steps

f^{'} (x) = e^{x^{2} - 4} \cdot 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

e^{x^{2} - 4} : \frac{1}{e ^{4}}

Minimum (0, \frac{1}{e ^{4}})

Graph

Popular Examples

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f (x) = (\frac{x ^{5}}{5} - 1)^{\frac{1}{3}}

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extreme f(x)= 1/(x^2-6x+12)extreme points

f (x) = \frac{1}{x ^{2} - 6 x + 12}

domain of f(x)=|2x+3|domain

f (x) = ∣ 2 x + 3 ∣

inflection f(x)=x^5-20x^2 inflection points

f (x) = x^{5} - 20 x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=e^{x^2-4} ?
The extreme f(x)=e^{x^2-4} is Minimum(0, 1/(e^4))