What is the perpendicular 9x+12y+13=0 ?

The perpendicular 9x+12y+13=0 is y= 4/3 x+b

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perpendicular 9x+12y+13=0

perpendicular

9 x + 12 y + 13 = 0

y = \frac{4}{3} x + b

Solution steps

Find the slope of

9 x + 12 y + 13 = 0 : m = - \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = \frac{4}{3}

Line with slope m=

\frac{4}{3} : y = \frac{4}{3} x + b

y = \frac{4}{3} x + b

y = 6^{x} + 3

f (x) = \frac{1}{3} x

\frac{9 - 3 x}{x - 5}

x^{3} + 8

x - 1

What is the perpendicular 9x+12y+13=0 ?
The perpendicular 9x+12y+13=0 is y= 4/3 x+b