What is the slope ofintercept-x+4y=0 ?

The slope ofintercept-x+4y=0 is y= 1/4 x+0

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slope ofintercept-x+4y=0

slope intercept

- x + 4 y = 0

y = \frac{1}{4} x + 0

Solution steps

- x + 4 y = 0

Convert to slope intercept form:

y = \frac{1}{4} x

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = \frac{1}{4} x + 0

y = - 2 x + 6 y

y = 4 x - 8

f (x) = - 5 x^{2}

f (x) = - \frac{1}{3} x + 1

f (x) = (x - 1)^{2} + 2

What is the slope ofintercept-x+4y=0 ?
The slope ofintercept-x+4y=0 is y= 1/4 x+0