What is the perpendicular y=-7/2 x-2,(7,-5) ?

The perpendicular y=-7/2 x-2,(7,-5) is y= 2/7 x-7

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perpendicular y=-7/2 x-2,(7,-5)

perpendicular

y = - \frac{7}{2} x - 2, (7, - 5)

y = \frac{2}{7} x - 7

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{7}{2} x - 2

that passes through

(7, - 5)

Find the slope of

y = - \frac{7}{2} x - 2 : m = - \frac{7}{2}

Compute the slope of the perpendicular line:

m_{p} = \frac{2}{7}

Find the line with slope m=

\frac{2}{7}

and passing through

(7, - 5) : y = \frac{2}{7} x - 7

y = \frac{2}{7} x - 7

x + 8

\frac{4}{5} (- 15.5)

\frac{6}{x - 5} + 1

f (x) = \frac{x ^{2} + 4 x}{- 4 x ^{2} + 36}

f (c) = \frac{9}{5} c + 32

What is the perpendicular y=-7/2 x-2,(7,-5) ?
The perpendicular y=-7/2 x-2,(7,-5) is y= 2/7 x-7