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Popular >

midpoint (3,8),(2,-1)

Solution

midpoint

(3, 8), (2, - 1)

Solution

(\frac{5}{2}, \frac{7}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, 8), (x_{2}, y_{2}) = (2, - 1)

= (\frac{2 + 3}{2}, \frac{- 1 + 8}{2})

Refine

= (\frac{5}{2}, \frac{7}{2})

Popular Examples

inflection f(x)=x^3+3x+9 inflection points

f (x) = x^{3} + 3 x + 9

parity f(x)=(5x)/(x^3-2x)parity

f (x) = \frac{5 x}{x ^{3} - 2 x}

inverse of f(x)=log_{e}(x^2-1)inverse

f (x) = lo g_{e} (x^{2} - 1)

extreme f(x)=(2x^2)/((x-1)^2)extreme points

f (x) = \frac{2 x ^{2}}{( x - 1 ) ^{2}}

symmetry y=5x^2+6x+9 symmetry

y = 5 x^{2} + 6 x + 9

Frequently Asked Questions (FAQ)

What is the midpoint (3,8),(2,-1) ?
The midpoint (3,8),(2,-1) is (5/2 , 7/2)