What is the inverse of f(x)=log_{e}(x^2-1) ?

The inverse of f(x)=log_{e}(x^2-1) is sqrt(e^x+1),-sqrt(e^x+1)

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inverse of f(x)=log_{e}(x^2-1)

inverse

f (x) = lo g_{e} (x^{2} - 1)

e^{x} + 1, - e^{x} + 1

Solution steps

y = lo g_{e} (x^{2} - 1)

Replace

x

with

y

x = lo g_{e} (y^{2} - 1)

Solve for

y, x = lo g_{e} (y^{2} - 1)

e^{x} + 1, - e^{x} + 1

f (x) = \frac{2 x ^{2}}{( x - 1 ) ^{2}}

y = 5 x^{2} + 6 x + 9

6 e^{x + 1} - 3

\frac{ln ( x )}{x}

\frac{x + 5}{x ^{2} - 9}

What is the inverse of f(x)=log_{e}(x^2-1) ?
The inverse of f(x)=log_{e}(x^2-1) is sqrt(e^x+1),-sqrt(e^x+1)