What is the domain of (x+5)/(x^2-9) ?

The domain of (x+5)/(x^2-9) is x 3

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domain of (x+5)/(x^2-9)

domain

\frac{x + 5}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

lo g_{4} (x + 2) - 2 lo g_{4} (1 - x) + 1

f (x) = \frac{( - 7 x ^{2} )}{4 x - 3}

f (x) = \frac{9 - 7 x}{6 + 9 x}

4 x + 5 y = 6

f (x) = - 5 (x + 4)^{2} + 2

What is the domain of (x+5)/(x^2-9) ?
The domain of (x+5)/(x^2-9) is x<-3\lor-3<x<3\lor x>3