What is the shift 1/4 cos(1/4 x-pi/(12)) ?

The shift 1/4 cos(1/4 x-pi/(12)) is Phase: pi/3 , Vertical:0

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shift 1/4 cos(1/4 x-pi/(12))

shift

\frac{1}{4} cos (\frac{1}{4} x - \frac{π}{12})

Phase : \frac{π}{3}, Vertical : 0

Solution steps

f (x) = \frac{1}{4} cos (\frac{1}{4} x - \frac{π}{12})

g (B x - C) = cos (\frac{1}{4} x - \frac{π}{12}), B = \frac{1}{4}, C = \frac{π}{12}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{12}}{\frac{1}{4}}

\frac{π}{3}

The vertical shift

D

0

0

f (x) = \frac{2}{\frac{1}{x} + 3}

f (x) = 36 - x^{2}

\frac{x + x ( 2 x ^{2} - 5 )}{2 x ^{2} - 5}

f (x) = 5 x^{\frac{1}{3}} + 4

f (x) = \frac{3 x - 9}{- 2 x + 3}

What is the shift 1/4 cos(1/4 x-pi/(12)) ?
The shift 1/4 cos(1/4 x-pi/(12)) is Phase: pi/3 , Vertical:0