What is the domain of f(x)=sqrt(4-x)+sqrt(x^2-1) ?

The domain of f(x)=sqrt(4-x)+sqrt(x^2-1) is x<=-1\lor 1<= x<= 4

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domain of f(x)=sqrt(4-x)+sqrt(x^2-1)

domain

f (x) = 4 - x + x^{2} - 1

x \leq - 1 or 1 \leq x \leq 4

Interval Notation

(- \infty, - 1] \cup [1, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 1 or 1 \leq x \leq 4

The function domain

x \leq - 1 or 1 \leq x \leq 4

f (x) = x^{2} + 2, x \geq 0

4 x - 7 y = - 28

f (x) = 2 x^{2} - 39

f (x) = - (x^{2} + x - 42)

f (x) = 3 x^{3} - 9 x

What is the domain of f(x)=sqrt(4-x)+sqrt(x^2-1) ?
The domain of f(x)=sqrt(4-x)+sqrt(x^2-1) is x<=-1\lor 1<= x<= 4