What is the monotone sqrt((2-x^2)/(x+1)) ?

The monotone sqrt((2-x^2)/(x+1)) is Decreasing:-1<x<sqrt(2)

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monotone sqrt((2-x^2)/(x+1))

monotone intervals

\frac{2 - x ^{2}}{x + 1}

Decreasing : - 1 < x < 2

Solution steps

f^{'} (x) = \frac{- x ^{2} - 2 x - 2}{2 - x ^{2} + 2 ( x + 1 ) ^{\frac{3}{2}}}

Find intervals:

Decreasing

: - 1 < x < 2

Decreasing : - 1 < x < 2

y = x^{2} + 10 x + 24

g (x) = x^{2} + 8 x

\frac{1}{2 x ^{3} - 4 x}

\frac{5 x - 2}{x + 9}

f (x) = x^{5} - x

What is the monotone sqrt((2-x^2)/(x+1)) ?
The monotone sqrt((2-x^2)/(x+1)) is Decreasing:-1<x<sqrt(2)