What is the inverse of f(x)=(x-1)^2-2 ?

The inverse of f(x)=(x-1)^2-2 is sqrt(x+2)+1,-sqrt(x+2)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-1)^2-2

inverse

f (x) = (x - 1)^{2} - 2

x + 2 + 1, - x + 2 + 1

Solution steps

y = (x - 1)^{2} - 2

Replace

x

with

y

x = (y - 1)^{2} - 2

Solve for

y, x = (y - 1)^{2} - 2

x + 2 + 1, - x + 2 + 1

y = \frac{3}{2} x + 1

f (x) = \frac{2}{( x - 1 )}

e^{- x} - 1

sin (1 - x^{2})

f (x) = (\frac{3}{2})

What is the inverse of f(x)=(x-1)^2-2 ?
The inverse of f(x)=(x-1)^2-2 is sqrt(x+2)+1,-sqrt(x+2)+1