What is the domain of sin(sqrt(1-x^2)) ?

The domain of sin(sqrt(1-x^2)) is -1<= x<= 1

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domain of sin(sqrt(1-x^2))

domain

sin (1 - x^{2})

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

f (x) = (\frac{3}{2})

f (x) = \frac{3 x}{2 x + 3}

x + y = 8

\frac{6}{( x - 1 ) ^{3}}

f (x) = \frac{x + 1}{x - 3}

What is the domain of sin(sqrt(1-x^2)) ?
The domain of sin(sqrt(1-x^2)) is -1<= x<= 1