What is the domain of f(x)=(sqrt(x+1))/(x-3) ?

The domain of f(x)=(sqrt(x+1))/(x-3) is -1 3

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domain of f(x)=(sqrt(x+1))/(x-3)

domain

f (x) = \frac{x + 1}{x - 3}

- 1 \leq x < 3 or x > 3

Interval Notation

[- 1, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 1 \leq x < 3 or x > 3

y = 3 x^{2} - 6 x + 4

f (x) = (x^{2} - 4)^{\frac{2}{3}}

2 x^{3} - 24 x - 5

f (x) = \frac{x}{4}

f (x) = (x - 3)^{2}

What is the domain of f(x)=(sqrt(x+1))/(x-3) ?
The domain of f(x)=(sqrt(x+1))/(x-3) is -1<= x<3\lor x>3