What is the critical f(x)=2sqrt(x^2+1)-x ?

The critical f(x)=2sqrt(x^2+1)-x is x= 1/(sqrt(3))

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critical f(x)=2sqrt(x^2+1)-x

critical points

f (x) = 2 x^{2} + 1 - x

x = \frac{1}{3}

Solution steps

2 x^{2} + 1 - x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

2 x^{2} + 1 - x : - \infty < x < \infty

All critical points are in domain

x = \frac{1}{3}

f (x) = 15 (\frac{1}{3})^{x}

f (x) = \frac{( 3 x - 5 )}{( 2 x + 7 )}

f (x) = - 6 x - 7

f (x) = 2.8 + 4.2 x - 1.6 x^{2}

f (x) = \frac{4 x + 9}{3 x - 6}

What is the critical f(x)=2sqrt(x^2+1)-x ?
The critical f(x)=2sqrt(x^2+1)-x is x= 1/(sqrt(3))