What is the perpendicular y=x-3,(2,1) ?

The perpendicular y=x-3,(2,1) is y=-x+3

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perpendicular y=x-3,(2,1)

perpendicular

y = x - 3, (2, 1)

y = - x + 3

Solution steps

Find the line

y = mx + b

perpendicular to

y = x - 3

that passes through

(2, 1)

Find the slope of

y = x - 3 : m = 1

Compute the slope of the perpendicular line:

m_{p} = - 1

Find the line with slope m=

- 1

and passing through

(2, 1) : y = - x + 3

y = - x + 3

f (x) = \frac{x - 2}{( x - 2 ) ^{2}}

f (x) = \frac{1}{x - 4} + 1

(0, 0), (r, h)

y = ln (x + 3)

3 x + 6 y = 5