What is the domain of f(x)= 1/(sqrt(9-x^2)) ?

The domain of f(x)= 1/(sqrt(9-x^2)) is -3<x<3

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domain of f(x)= 1/(sqrt(9-x^2))

domain

f (x) = \frac{1}{9 - x ^{2}}

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

f (x) = \frac{2}{3} x^{2} + 4 x + 1

f (x) = x^{4} - 32 x^{2} - 4

(2, 3), (7, - 7)

f (x) = tan (π x)

f (x) = x^{3} - 2 x^{2} - 4 x + 3

What is the domain of f(x)= 1/(sqrt(9-x^2)) ?
The domain of f(x)= 1/(sqrt(9-x^2)) is -3<x<3