What is the extreme f(x)=x^4-32x^2-4 ?

The extreme f(x)=x^4-32x^2-4 is Minimum(-4,-260),Maximum(0,-4),Minimum(4,-260)

Popular >

extreme f(x)=x^4-32x^2-4

extreme points

f (x) = x^{4} - 32 x^{2} - 4

Minimum (- 4, - 260), Maximum (0, - 4), Minimum (4, - 260)

Solution steps

f^{'} (x) = 4 x^{3} - 64 x

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

x^{4} - 32 x^{2} - 4 : - 260

Minimum (- 4, - 260)

Plug

x = 0

into

x^{4} - 32 x^{2} - 4 : - 4

Maximum (0, - 4)

Plug

x = 4

into

x^{4} - 32 x^{2} - 4 : - 260

Minimum (4, - 260)

Minimum (- 4, - 260), Maximum (0, - 4), Minimum (4, - 260)

(2, 3), (7, - 7)

f (x) = tan (π x)

f (x) = x^{3} - 2 x^{2} - 4 x + 3

f (x) = \frac{6 x ^{2} - 19 x + 8}{2 x - 1}

f (x) = \frac{x ^{2} - 9}{x - 3}

What is the extreme f(x)=x^4-32x^2-4 ?
The extreme f(x)=x^4-32x^2-4 is Minimum(-4,-260),Maximum(0,-4),Minimum(4,-260)