What is the perpendicular x+4y=6,(3,2) ?

The perpendicular x+4y=6,(3,2) is y=4x-10

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perpendicular x+4y=6,(3,2)

perpendicular

x + 4 y = 6, (3, 2)

y = 4 x - 10

Solution steps

Find the line

y = mx + b

perpendicular to

x + 4 y = 6

that passes through

(3, 2)

Find the slope of

x + 4 y = 6 : m = - \frac{1}{4}

Compute the slope of the perpendicular line:

m_{p} = 4

Find the line with slope m=

4

and passing through

(3, 2) : y = 4 x - 10

y = 4 x - 10

\frac{x ^{2} - 16}{x + 4}

f (x) = 1 + (2 + x)^{\frac{1}{2}}

(4.9, - 1.3), (- 5.2, - 0.6)

x^{3} - 3 x^{2} + 3 x + 9

5 \cdot 2^{x}

What is the perpendicular x+4y=6,(3,2) ?
The perpendicular x+4y=6,(3,2) is y=4x-10