What is the domain of (1/(sqrt(x)))^2-4 ?

The domain of (1/(sqrt(x)))^2-4 is x>0

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domain of (1/(sqrt(x)))^2-4

domain

(\frac{1}{x})^{2} - 4

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = \frac{9 - x ^{2}}{x + 1}

f (x) = \frac{3 x + 4}{2 x - 3}

f (x) = \frac{x ^{2} - 16}{x + 4}

f (x) = x - 1

\frac{1}{x ^{4} - 10 x ^{2} + 9}

What is the domain of (1/(sqrt(x)))^2-4 ?
The domain of (1/(sqrt(x)))^2-4 is x>0