What is the domain of f(x)=sqrt(169-x^2) ?

The domain of f(x)=sqrt(169-x^2) is -13<= x<= 13

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domain of f(x)=sqrt(169-x^2)

domain

f (x) = 169 - x^{2}

- 13 \leq x \leq 13

Interval Notation

[- 13, 13]

Solution steps

Find non-negative values for radicals:

- 13 \leq x \leq 13

The function domain

- 13 \leq x \leq 13

y = - 2

5 x + 2 y = 9

f (x) = arcsin (\frac{x + 2}{5 - x})

f (x) = 1650 ((1.022))^{t}

\frac{5}{x}

What is the domain of f(x)=sqrt(169-x^2) ?
The domain of f(x)=sqrt(169-x^2) is -13<= x<= 13