What is the inverse of f(x)=(4x-2)/(3x+1) ?

The inverse of f(x)=(4x-2)/(3x+1) is (-2-x)/(3x-4)

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inverse of f(x)=(4x-2)/(3x+1)

inverse

f (x) = \frac{4 x - 2}{3 x + 1}

\frac{- 2 - x}{3 x - 4}

Solution steps

y = \frac{4 x - 2}{3 x + 1}

Replace

x

with

y

x = \frac{4 y - 2}{3 y + 1}

Solve for

y, x = \frac{4 y - 2}{3 y + 1}

\frac{- 2 - x}{3 x - 4}

(13, - 5), (- 10, 0)

f (x) = \frac{( x + 1 )}{x + 2}

f (x) = \frac{( x + 18 )}{( x - 17 )}

x = - \frac{2}{3} y - 2

f (x) = x^{3} - 6 x^{2} + 9 x + 4

What is the inverse of f(x)=(4x-2)/(3x+1) ?
The inverse of f(x)=(4x-2)/(3x+1) is (-2-x)/(3x-4)