What is the inverse of f(x)=(x+1)^2+2 ?

The inverse of f(x)=(x+1)^2+2 is sqrt(x-2)-1,-sqrt(x-2)-1

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inverse of f(x)=(x+1)^2+2

inverse

f (x) = (x + 1)^{2} + 2

x - 2 - 1, - x - 2 - 1

Solution steps

y = (x + 1)^{2} + 2

Replace

x

with

y

x = (y + 1)^{2} + 2

Solve for

y, x = (y + 1)^{2} + 2

x - 2 - 1, - x - 2 - 1

\frac{x - 6}{- 3 x}

sin (2) (x - \frac{π}{2}) + 1

f (x) = \frac{x ^{3}}{3} - 4 x

f (x) = \frac{( x + 3 )}{4}

y = \frac{3}{x + 4} + 2

What is the inverse of f(x)=(x+1)^2+2 ?
The inverse of f(x)=(x+1)^2+2 is sqrt(x-2)-1,-sqrt(x-2)-1