What is the inverse of 2x^2(sqrt(2)+1) ?

The inverse of 2x^2(sqrt(2)+1) is sqrt(((\sqrt{2)-1)x)/2},-sqrt(((\sqrt{2)-1)x)/2}

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inverse of 2x^2(sqrt(2)+1)

inverse

2 x^{2} (2 + 1)

\frac{( 2 - 1 ) x}{2}, - \frac{( 2 - 1 ) x}{2}

Solution steps

y = 2 x^{2} (2 + 1)

Replace

x

with

y

x = 2 y^{2} (2 + 1)

Solve for

y, x = 2 y^{2} (2 + 1)

\frac{( 2 - 1 ) x}{2}, - \frac{( 2 - 1 ) x}{2}

x = \frac{3}{5}

f (x) = 2 x - 8

f (x) = x + 2 y = 5

sin (x) + cos^{2} (x)

\frac{ln ( x - 2 )}{( x - 2 ) ^{2}}

What is the inverse of 2x^2(sqrt(2)+1) ?
The inverse of 2x^2(sqrt(2)+1) is sqrt(((\sqrt{2)-1)x)/2},-sqrt(((\sqrt{2)-1)x)/2}