What is the domain of h(x)=sqrt(3x-12) ?

The domain of h(x)=sqrt(3x-12) is x>= 4

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domain of h(x)=sqrt(3x-12)

domain

h (x) = 3 x - 12

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

The function domain

x \geq 4

f (x) = \frac{x ^{2} - 4}{2 x - 4}

f (x) = 8 x + 4

f (x) = \frac{2 x ^{2} + x - 18}{x ^{2} - 9}

f (x) = \frac{x}{1 - ln ( x - 6 )}

\frac{3 x}{x ^{2} - 4}

What is the domain of h(x)=sqrt(3x-12) ?
The domain of h(x)=sqrt(3x-12) is x>= 4