What is the inverse of y= 1/2 sqrt(4-x^2) ?

The inverse of y= 1/2 sqrt(4-x^2) is 2sqrt(-x^2+1),-2sqrt(-x^2+1)

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inverse of y= 1/2 sqrt(4-x^2)

inverse

y = \frac{1}{2} 4 - x^{2}

2 - x^{2} + 1, - 2 - x^{2} + 1

Solution steps

y = \frac{1}{2} 4 - x^{2}

Replace

x

with

y

x = \frac{1}{2} 4 - y^{2}

Solve for

y, x = \frac{1}{2} 4 - y^{2}

2 - x^{2} + 1, - 2 - x^{2} + 1

f (x) = \frac{4}{5} x - 4 + 1

f (x) = 8 - 4 x

f (x) = \frac{x ^{2} + 3 x - 4}{x ( x ^{2} - 5 )}

3 x - y = 2

f (x) = - x + 5

What is the inverse of y= 1/2 sqrt(4-x^2) ?
The inverse of y= 1/2 sqrt(4-x^2) is 2sqrt(-x^2+1),-2sqrt(-x^2+1)