What is the domain of f(x)= 3/(x^2+4x-45) ?

The domain of f(x)= 3/(x^2+4x-45) is x 5

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domain of f(x)= 3/(x^2+4x-45)

domain

f (x) = \frac{3}{x ^{2} + 4 x - 45}

x < - 9 or - 9 < x < 5 or x > 5

Solution steps

Find undefined (singularity) points:

x = 5, x = - 9

The function domain

x < - 9 or - 9 < x < 5 or x > 5

f (x) = 6 cos (\frac{1}{5} π x - π) + 4

f (x) = x^{\frac{5}{4}}

f (x) = \frac{x}{4 - x ^{2}}

f (x) = \frac{7}{x ^{2} - 2 x - 24}

f (x) = ln (\frac{x + 1}{x + 2})

What is the domain of f(x)= 3/(x^2+4x-45) ?
The domain of f(x)= 3/(x^2+4x-45) is x<-9\lor-9<x<5\lor x>5