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Popular >

extreme f(x)=x^2+7x+8

Solution

extreme points

f (x) = x^{2} + 7 x + 8

Solution

Minimum (- \frac{7}{2}, - \frac{17}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

x^{2} + 7 x + 8 : - \frac{17}{4}

Minimum (- \frac{7}{2}, - \frac{17}{4})

Popular Examples

domain of f(x)=-9/(2t^{3/2)}domain

f (x) = - \frac{9}{2 t ^{\frac{3}{2}}}

domain of sqrt(2(x-3)+10)domain

2 (x - 3) + 10

domain of sqrt(x^2+2x-15)domain

x^{2} + 2 x - 15

extreme f(x)=x^3-3x^2-72x extreme points

f (x) = x^{3} - 3 x^{2} - 72 x

critical f(x)=x^{9/2}-4x^2 critical points

f (x) = x^{\frac{9}{2}} - 4 x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+7x+8 ?
The extreme f(x)=x^2+7x+8 is Minimum(-7/2 ,-17/4)