What is the domain of f(x)= 1/(\frac{2){x-5}-2} ?

The domain of f(x)= 1/(\frac{2){x-5}-2} is x 6

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domain of f(x)= 1/(\frac{2){x-5}-2}

domain

f (x) = \frac{1}{\frac{2}{x - 5} - 2}

x < 5 or 5 < x < 6 or x > 6

Interval Notation

(- \infty, 5) \cup (5, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = 5

The function domain

x < 5 or 5 < x < 6 or x > 6

f (x) = lo g_{\frac{1}{3}} (1 - x)

\frac{1}{∣ x ∣ + x}

f (x) = \frac{x ^{2} - 2}{x + 2}

f (x) = \frac{9 - x ^{2}}{x + 1}

(x - 3)^{3} + 4

What is the domain of f(x)= 1/(\frac{2){x-5}-2} ?
The domain of f(x)= 1/(\frac{2){x-5}-2} is x<5\lor 5<x<6\lor x>6