What is the inverse of f(x)=2x^2-x+1 ?

The inverse of f(x)=2x^2-x+1 is (1+sqrt(8x-7))/4 ,(1-sqrt(8x-7))/4

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inverse of f(x)=2x^2-x+1

inverse

f (x) = 2 x^{2} - x + 1

\frac{1 + 8 x - 7}{4}, \frac{1 - 8 x - 7}{4}

Solution steps

y = 2 x^{2} - x + 1

Replace

x

with

y

x = 2 y^{2} - y + 1

Solve for

y, x = 2 y^{2} - y + 1

\frac{1 + 8 x - 7}{4}, \frac{1 - 8 x - 7}{4}

m = 0, (2, 1)

(- 1.2) (5.4)

f (x) = - x^{2} + 4 x + 1

f (t) = \frac{4}{3 - t}

7 - x^{3}

What is the inverse of f(x)=2x^2-x+1 ?
The inverse of f(x)=2x^2-x+1 is (1+sqrt(8x-7))/4 ,(1-sqrt(8x-7))/4