What is the inverse of f(x)=(1-3x)/(3+2x) ?

The inverse of f(x)=(1-3x)/(3+2x) is (1-3x)/(2x+3)

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inverse of f(x)=(1-3x)/(3+2x)

inverse

f (x) = \frac{1 - 3 x}{3 + 2 x}

\frac{1 - 3 x}{2 x + 3}

Solution steps

y = \frac{1 - 3 x}{3 + 2 x}

Replace

x

with

y

x = \frac{1 - 3 y}{3 + 2 y}

Solve for

y, x = \frac{1 - 3 y}{3 + 2 y}

\frac{1 - 3 x}{2 x + 3}

f (x) = \frac{9}{x - 2}

f (x) = (x - 5)^{2} - 1

y = \frac{1}{t ^{2}} cos^{2} (t)

f (x) = (x^{2} - 3)^{2} (x^{2} + 3)^{2} = 0

What is the inverse of f(x)=(1-3x)/(3+2x) ?
The inverse of f(x)=(1-3x)/(3+2x) is (1-3x)/(2x+3)