What is the perpendicular 2x+3y=8,(-1,-2) ?

The perpendicular 2x+3y=8,(-1,-2) is y= 3/2 x-1/2

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perpendicular 2x+3y=8,(-1,-2)

perpendicular

2 x + 3 y = 8, (- 1, - 2)

y = \frac{3}{2} x - \frac{1}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

2 x + 3 y = 8

that passes through

(- 1, - 2)

Find the slope of

2 x + 3 y = 8 : m = - \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(- 1, - 2) : y = \frac{3}{2} x - \frac{1}{2}

y = \frac{3}{2} x - \frac{1}{2}

y = 3 x - 4, (- 4, 5)

f (x) = \frac{3 x + 1}{4 x ^{2} - 1}

(- 4, - 3), (6, - 7)

f (x) = \frac{9}{x ^{2} - 16}

\frac{1}{( x - 3 ) ^{3}}

What is the perpendicular 2x+3y=8,(-1,-2) ?
The perpendicular 2x+3y=8,(-1,-2) is y= 3/2 x-1/2